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First, calculate Z2 R2 X2 50.02 ( 50.0)2 2500 2500 square root of 5000, or 70.7 . Then I E/Z 100/70.7 1.41 A.

Serin 1, 16468, [WAIT ("DECODE")] Debug "password accepted"

A month later he was second-guessing himself as Lucent continued its rise to $75 Ultimately, the market realized that LU had no clothes From that $75 peak, the stock price declined steadily (see Exhibit 3-3) to $126 per share on December 31, 2002 The reality underlying the high-tech bubble is that all investors individuals and institutions, domestic and foreign, women and men, workers and retirees bid stock prices of companies up to unrealistic levels The operating profits of the underlying businesses of the companies could never support the overvaluation by the market We all participated in this stupid activity We all are at fault We all are guilty True, the stock analysts of Wall Street urged us to pay up to buy shares of these great companies Henrico, the Internet analyst said, No price is too high for a great company.

Problem 16-21

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In this example, Serin waits for that word, and the program will not continue until it is received. Serin is looking for an exact match; i.e., the word DECODE in capital letters has to be sent from a keyboard in order for the password accepted message to be displayed. Some typical STAMP 2 Serout commands are quite similar to the Serin commands and are shown below.

What are the voltage drops across the resistance and the reactance, respectively, in the above problem The Ohm s Law formulas for dc will work here. Because the current is I 1.41 A, the voltage drop across the resistance is equal to ER IR 1.41 50.0 70.5 V. The voltage drop across the reactance is the product of the current and the reactance: EX IX 1.41 ( 50.0) 70.5. This is an ac voltage of equal magnitude to that across the resistance. But the phase is different. The voltages across the resistance and the reactance a capacitive reactance in this case, because it s negative don t add up to 100. The meaning of the minus sign for the voltage across the capacitor is unclear, but there is no way, whether you consider this sign or not, that the voltages across the resistor and capacitor will arithmetically add up to 100. Shouldn t they In a dc circuit, yes; in an ac circuit, generally, no. In a resistance-reactance ac circuit, there is always a difference in phase between the voltage across the resistive part and the voltage across the reactive part. They always add up to the applied voltage vectorially, but not always arithmetically. You don t need to

300 RLC circuit analysis be concerned with the geometry of the vectors in this situation. It s enough to understand that the vectors don t fall along a single line, and this is why the voltages don t add arithmetically.

Serout tpin, baudmode, {pace,} [outputdata]

The real risk is not buying, standing on the sideline, seeing your aggressive, risk-taking neighbor or coworker make bundles in the market, while conservative, cautious YOU owns bonds and money market funds and misses the upward.

Problem 16-22

In the above example, tpin is the STAMP 2 I/O pin that will be used to send serial data. Baudmode is the setting for the bit rate, data bits, polarity, and drive, and pace is an optional delay between bytes in milliseconds.

A series RX circuit (Fig. 16-11) has R 10.0 and a net reactance X 40.0 . The applied voltage is 100. What is the current Calculate Z2 R2 X2 100 1600 1700; thus, Z 41.2. Therefore, I E/Z 100/41.2 2.43 A. Note that the reactance in this circuit is inductive, because it is positive.

Problem 16-23

Serout 1, 16468, [Greetings!"]

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